Answer
$x=0.368$
Work Step by Step
$\frac{1+\ln x}{2}=0$
$1+\ln x=0$
$\ln x=-1$
$e^{\ln x}=e^{-1}$
$x=0.368$
Notice that $0.368$ lies in the domain of $\ln x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 77
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