Answer
$x=0$
$x=2$
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Work Step by Step
$-x^2e^{-x}+2xe^{-x}=0$
$-xe^{-x}(x-2)=0$
Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$
$-xe^{-x}=0$
$x=0$
$x-2=0$
$x=2$
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