Answer
$y=e^{0.09t}$ (Green)
$y=3$ (Red)
By observation of the graph:
Solution: $x\approx12.200$. It is just a visual approximation.
Algebraically:
$x=12.207$
Work Step by Step
$e^{0.09t}=3$
$\ln e^{0.09t}=\ln3$
$0.09t=\ln3$
$x=\frac{\ln3}{0.09}=12.207$
