Answer
$x=1$
Work Step by Step
$-xe^{-x}+e^{-x}=0$
$-e^{-x}(x-1)=0$
Since $e^{-x}\gt0$ for any $x$ in the domain of $e^{-x}$:
$x-1=0$
$x=1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 Exercises - Page 396: 75
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