Answer
$\log_2x^4\sqrt {\frac{y}{z^3}}=4\log_2x+\frac{\log_2y}{2}-\frac{3\log_2z}{2}$
Work Step by Step
$\log_2x^4\sqrt {\frac{y}{z^3}}=\log_2x^4+\log_2(\frac{y}{z^3})^\frac{1}{2}=4\log_2x+\frac{1}{2}\log_2\frac{y}{z^3}=4\log_2x+\frac{1}{2}(\log_2y-\log_2z^3)=4\log_2x+\frac{1}{2}(\log_2y-3\log_2z)=4\log_2x+\frac{\log_2y}{2}-\frac{3\log_2z}{2}$
