Answer
$\log_b10=1.1833$
Work Step by Step
$\log_b10=\log_b(2·5)=\log_b2+\log_b5=0.3562+0.8271=1.1833$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 385: 33
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