Answer
$\ln\sqrt[3] {\frac{yz}{x^2}}=\frac{\ln y}{3}+\frac{\ln z}{3}-\frac{2\ln z}{3}$
Work Step by Step
$\ln\sqrt[3] {\frac{yz}{x^2}}=\ln(\frac{yz}{x^2})^{\frac{1}{3}}={\frac{1}{3}}\ln\frac{yz}{x^2}=\frac{1}{3}(\ln yz-\ln x^2)=\frac{1}{3}(\ln y+\ln z-2\ln x)=\frac{\ln y}{3}+\frac{\ln z}{3}-\frac{2\ln z}{3}$
