Answer
$$ 2log_6(w) - log_6v$$
Work Step by Step
Using the rules of logarithms, we find:
$$log_6(w^2) - log_6(v) \\ 2log_6(w) - log_6v$$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 385: 46
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