Answer
$\ln\frac{3}{\sqrt {x^2+1}}=\ln3-\frac{1}{2}\ln(x^2+1)$
Work Step by Step
$\ln\frac{3}{\sqrt {x^2+1}}=\ln3-\ln\sqrt {x^2+1}=\ln3-\ln(x^2+1)^{\frac{1}{2}}=\ln3-\frac{1}{2}\ln(x^2+1)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 385: 54
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