Answer
$\begin{bmatrix}
27 & -6\\
-6 & -27\\
\end{bmatrix}$
Work Step by Step
First multiply the two matrices:
$\begin{bmatrix}
6(0) + 5(-1) + (-1)(4) & 6(3) + 5(-3) + (-1)(1)\\
1(0) + (-2)(-1) + 0(4) & 1(3) + (-2)(-3) + 0(1)\\
\end{bmatrix}$ = $\begin{bmatrix}
0-5-4 & 18-15-1\\
0+2+0 & 3+6+0\\
\end{bmatrix}$ = $\begin{bmatrix}
-9 & 2\\
2 & 9\\
\end{bmatrix}$
Then multiply the matrix found above by the scalar multiple -3:
$\begin{bmatrix}
-9(-3) & 2(-3)\\
2(-3) & 9(-3)\\
\end{bmatrix}$ = $\begin{bmatrix}
27 & -6\\
-6 & -27\\
\end{bmatrix}$
