Answer
Part A:
$\begin{bmatrix}
6\\
18\\
\end{bmatrix}$
Part B:
Not possible.
Part C:
Not possible.
Work Step by Step
A has 2 rows and 3 columns (2 x 3).
B has 3 rows and 1 column (3 x 1).
Part A:
$\begin{bmatrix}
1(3) + 3(3) + (-2)(3)\\
(-5)(3) + 10(3) + 1(3)\\
\end{bmatrix}$ = $\begin{bmatrix}
3 + 9 - 6\\
-15 + 30 + 3\\
\end{bmatrix}$ = $\begin{bmatrix}
6\\
18\\
\end{bmatrix}$
Part B:
Since the number of columns in B does not equal the number of rows in A, BA is not possible.
Part C:
Since the number of columns in A does not equal the number of rows in A, AA is not possible.
