Answer
-3, 1
Work Step by Step
$4/(x+1)-3/(x+2)=1$
4(x+2)-3(x+1)=(x+1)(x+2)
$x+5 = x^2+3x+2$
$x^2+2x-3 = x^2+3x-x-3=x(x+3)-1(x+3)=0$
$(x+3)(x-1)=0$, giving x=-3 or 1
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 54
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