Answer
$\frac{-3+\sqrt {21}}{6}, \frac{-3-\sqrt {21}}{6}$
Work Step by Step
$1/x - 1/(x+1)=3$
$x+1 - x= 3x(x+1)$
$1 = 3x^2+3x$
$3x^2+3x-1=0$ Using the discriminant rule for quadratic equations to find the roots we get x= $\frac{-3+\sqrt {21}}{6}$ or $ \frac{-3-\sqrt {21}}{6}$
