Answer
$+1, -1 , \sqrt3, -\sqrt3$
Work Step by Step
$x^4-4x^2+3=0$
$(x^2-3)(x^2-1)=0$
$x^2-1=(x-1)(x+1)=0$ gives x=1 or -1
$x^2-3=(x-\sqrt3)(x+\sqrt3)=0$ gives $x= \sqrt3$ or $-\sqrt3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 17
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