Answer
$x=16$
Work Step by Step
$\sqrt {3x+1}=7~~$ (Square both sides)
$(\sqrt {3x+1})^2=7^2$
$3x+1=49$
$3x=48$
$x=\frac{48}{3}=16$
Check the solution;
$\sqrt {3(16)+1}=\sqrt {48+1}=\sqrt {49}=7$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 34
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