Answer
-64/27
Work Step by Step
Let a=$t^{\frac{1}{3}}$
$9a^2+24a+16=(3a+4)^2=0$
a = -4/3
$t^{\frac{1}{3}}=-4/3$
t=-64/27
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 29
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