Answer
1, -125/8
Work Step by Step
Let a=$x^{\frac{1}{3}}$
$3a+2a^2=5$
$2a^2-2+3a-3=2(a^2-1)+3(a-1)=2(a-1)(a+1)+3(a-1)=(a-1)(2a+5)=0$
Either a=1 giving $x^{\frac{1}{3}}=1$, x=1
or a=-5/2 giving $x^{\frac{1}{3}}=-5/2$, x=-125/8
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 30
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