Appendix A - A Exercises - Page A6: 43

$$\frac{4x^3}{x^{1/3}}-\frac{7x^2}{x^{1/3}}+\frac{1}{x^{1/3}}$$

We can split each component in the numerator up by making separate fractions, all with the same denominator. Thus, we find: $$\frac{4x^3}{x^{1/3}}-\frac{7x^2}{x^{1/3}}+\frac{1}{x^{1/3}}$$