Answer
It is verified that the two expressions are equivalent.
$\frac{x^2}{\frac{3}{10}}-\frac{y^2}{\frac{4}{5}}=\frac{10x^2}{3}-\frac{5y^2}{4}$
Work Step by Step
$\frac{x^2}{\frac{3}{10}}-\frac{y^2}{\frac{4}{5}}=\frac{x^2}{\frac{3}{10}}\frac{10}{10}-\frac{y^2}{\frac{4}{5}}\frac{5}{5}=\frac{10x^2}{3}-\frac{5y^2}{4}$
