Appendix A - A Exercises - Page A6: 40

$$x(x-2)^{-1}+x^{-2} + 8/3(9x)^{-3}$$

We know that we can take values from the denominator to the numerator by putting a negative in front of the power that they are raised to. Thus, we see that this expression becomes: $$x(x-2)^{-1}+x^{-2} + 8/3(9x)^{-3}$$