Answer
$$x^{\frac{1}{2}}(10x+3)$$
Work Step by Step
$3(2x+1)x^{\frac{1}{2}}+4x^{\frac{3}{2}}=3(2x+1)x^{\frac{1}{2}}+4x^{\frac{1}{2}+1}=(6x+3)x^{\frac{1}{2}}+4x(x^{\frac{1}{2}})=x^{\frac{1}{2}}(6x+3+4x)=x^{\frac{1}{2}}(10x+3)$
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