Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Appendix A - A Exercises - Page A6: 13

Answer

$2x(x+2)^{-\frac{1}{2}}+(x+2)^{\frac{1}{2}}=(x+2)^{-\frac{1}{2}}(3x+2)$

Work Step by Step

$2x(x+2)^{-\frac{1}{2}}+(x+2)^{\frac{1}{2}}=2x(x+2)^{-\frac{1}{2}}+(x+2)^{-\frac{1}{2}+1}=2x(x+2)^{-\frac{1}{2}}+(x+2)^{-\frac{1}{2}}(x+2)=(x+2)^{-\frac{1}{2}}(2x+x+2)=(x+2)^{-\frac{1}{2}}(3x+2)$
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