Answer
$$4(3x)^{-1} + 4x^{-4} -7x(2x)^{-\frac{2}{3}}$$
Work Step by Step
We know that we can take values from the denominator to the numerator by putting a negative in front of the power that they are raised to. Thus, we see that this expression becomes:
$$4(3x)^{-1} + 4x^{-4} -7x(2x^{-\frac{2}{3}})$$
