Answer
It is verified that the two expressions are equivalent.
$\frac{4x}{14}-2y^2=\frac{2x^2}{7}-\frac{y^2}{\frac{1}{2}}$
Work Step by Step
$\frac{4x}{14}-2y^2=\frac{4x}{14}\frac{\frac{1}{2}}{\frac{1}{2}}-2y^2\frac{\frac{1}{2}}{\frac{1}{2}}=\frac{2x^2}{7}-\frac{y^2}{\frac{1}{2}}$
