Answer
$a_n=36-11n$ ; $a_{20}=-184$
Work Step by Step
We know that $a_n= a_1+(n-1) d$
Here, we have $d=14-25=-11$
$a_n= (25)+(n-1) \times (-11)$
This gives: $a_n=36-11n$
$a_{20}=36-11 \times 20=-184$
Hence, $a_n=36-11n$ ; $a_{20}=-184$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Skill Practice - Page 806: 17
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
