Answer
$a_n=10-4n$ ; $a_{20}=-70$
Work Step by Step
We know that $a_n= a_1+(n-1) d$
Here, we have $d=2-6=-4$
$a_n= (6)+(n-1) \times (-4)$
This gives: $a_n=10-4n$
$a_{20}=10-4 \times 20=-70$
Hence, $a_n=10-4n$ ; $a_{20}=-70$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.2 Analyze Arithmetic Sequences and Series - 12.2 Exercises - Skill Practice - Page 806: 16
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