Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 754: 32

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Use the formula of combination: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$. Plug in 3 for N and 0 for R: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$ $_{3}$C$_{0}$=$\frac{3!}{0!(3-0)!}$ -simplify like terms- $_{3}$C$_{0}$=$\frac{3!}{0! (3!)}$ -write using factorial- $_{3}$C$_{0}$=$\frac{3*2*1}{(1)(3*2*1)}$ -simplify- $_{3}$C$_{0}$=1