Answer
The frictional force acting on the vehicle has a magnitude of $130N$.
Work Step by Step
Mass of the vehicle $m=5.9\times10^3kg$
In tests on earth, to achieve $a=0.22m/s^2$, the drive force required is, according to Newton's 2nd Law, $$F=ma=1.3\times10^3N$$
We know from Newton's 2nd Law and Conceptual Example 7 that the calculated $F$ above is the same on earth and on the moon, as mass $m$ does not change as the vehicle goes to the moon. Therefore, the increase in the required drive force on the moon is attributed to friction.
We have $F_{moon}=1.43\times10^3N$
$$F_{moon}=F+f$$ $$f=F_{moon}-F=130N$$