Answer
The skydiver's acceleration has a magnitude of $1.2m/s^{2}$ and is directed upward.
Work Step by Step
Let's take upward to be $+y$ direction. Therefore, $W=-915N$ and $F_{drag}=1027N$.
The total force acting on the skydiver is $$\sum F=W+F_{drag}=1027-915=112N$$
The mass of the skydiver $m=93.4kg$. The acceleration of the skydiver, according to Newton's 2nd Law of Motion, would be $$a=\frac{\sum F}{m}=1.2m/s^{2}$$
The magnitude of $a$ is $1.2m/s^{2}$. Since $a\gt0$, its direction follows $+y$ direction, which means it points upward.
