Answer
de Broglie wavelength of bacterium is $\lambda=1.0045\times10^{-18}m$
Work Step by Step
mass of the bacterium $m= 2\times10^{-15}kg$
speed of bacterium $v=0.33m/s$
by de Broglie hypothesis
de-Broglie wavelength is given by $\lambda=\frac{h}{mv}$
putting $h=6.63\times10^{-34}J$, $m= 2\times10^{-15}kg$, $v=0.33m/s$
$\lambda=\frac{6.63\times10^{-34}J}{2\times10^{-15}kg\times0.33m/s}$
$\lambda=10.045\times^{-19}m=1.0045\times10^{-18}m$
