Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 254: 98a

Answer

$\Delta p = (-0.45~kg~m/s)~\hat{i}-(0.45~kg~m/s)~\hat{j}-(1.08~kg~m/s)~\hat{k}$

Work Step by Step

$v_i = (5.00~m/s)~\hat{i}+(6.50~m/s)~\hat{j}+(4.00~m/s)~\hat{k}$ $v_f = (2.00~m/s)~\hat{i}+(3.50~m/s)~\hat{j}+(-3.20~m/s)~\hat{k}$ We can find the change in velocity: $\Delta v = v_f - v_i$ $\Delta v = -(3.00~m/s)~\hat{i}-(3.00~m/s)~\hat{j}-(7.20~m/s)~\hat{k}$ We can find the change in momentum: $\Delta p = m~\Delta v$ $\Delta p = (0.15~kg)[-(3.00~m/s)~\hat{i}-(3.00~m/s)~\hat{j}-(7.20~m/s)~\hat{k}]$ $\Delta p = (-0.45~kg~m/s)~\hat{i}-(0.45~kg~m/s)~\hat{j}-(1.08~kg~m/s)~\hat{k}$
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