Answer
0.8 m/s
Work Step by Step
$V_{1} = 1.59m/s$
$V_{2} = 1.37m/s$
$\theta_{2} = 30.3˚$
$V_{1f} = \frac{sin\theta_{1}}{sin(\theta_{1}+\theta_{2})} $
$V_{1f} = \frac{sin30}{sin(30+60)} $
= $\frac{sin30}{sin(30+60)}(1.59) $
= 0.8 m/s
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 254: 95a
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