Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 254: 96a

Answer

The thrust of the engine is $~~8.0\times 10^4~N$

Work Step by Step

We can use Newton's Second Law to find the thrust $F$ of the engine: $F = ma$ $F = (4.0\times 10^4~kg)(2.0~m/s^2)$ $F = 8.0\times 10^4~N$ The thrust of the engine is $~~8.0\times 10^4~N$
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