Answer
The total kinetic energy before separation is $~~1.27\times 10^{10}~J$
Work Step by Step
We can find the total kinetic energy before separation:
$K = \frac{1}{2}mv^2$
$K = \frac{1}{2}(290.0~kg+150.0~kg)(7600~m/s)^2$
$K = 1.27\times 10^{10}~J$
The total kinetic energy before separation is $~~1.27\times 10^{10}~J$.
