Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 253: 80c

Answer

The net force is zero.

Work Step by Step

$r = (3500 - 160t)~\hat{i} + 2700~\hat{j} + 300~\hat{k}$ $v = \frac{dr}{dt} = (-160~\hat{i})~m/s$ $a = \frac{dv}{dt} = 0$ We can use Newton's Second Law to find the net force: $F = ma$ $F = (250~kg)(0)$ $F = 0$ Since the acceleration is 0, the net force must also be 0.
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