Answer
The thrust is $~~1.57\times 10^6~N$
Work Step by Step
We can find the thrust:
$R~v_{rel} = (480~kg/s)(3270~m/s) = 1.57\times 10^6~N$
The thrust is $~~1.57\times 10^6~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 253: 79a
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