Answer
The final speed of the rocket is $~~2080~m/s$
Work Step by Step
In part (b), we found that the final mass of the rocket is $~~M_f = 1.35\times 10^5~kg$
We can use Equation (9-88) to find the final speed of the rocket:
$v_f-v_i = v_{rel}~ln(\frac{M_i}{M_f})$
$v_f = v_i + v_{rel}~ln(\frac{M_i}{M_f})$
$v_f = 0 + (3270~m/s)~ln(\frac{2.55\times 10^5~kg}{1.35\times 10^5~kg})$
$v_f = 0 + (3270~m/s)~ln(\frac{2.55}{1.35})$
$v_f = 2080~m/s$
The final speed of the rocket is $~~2080~m/s$.
