Answer
The magnitude of the linear momentum is $~~40,000~kg~m/s$
Work Step by Step
$r = (3500 - 160t)~\hat{i} + 2700~\hat{j} + 300~\hat{k}$
$v = \frac{dr}{dt} = (-160~\hat{i})~m/s$
We can find the linear momentum:
$p = m~v$
$p = (250~kg) (-160~\hat{i})~m/s$
$p = (-40,000~\hat{i})~kg~m/s$
The magnitude of the linear momentum is $~~40,000~kg~m/s$.
