Answer
$31.3kN$
Work Step by Step
Let $W$ be the weight (Given as $27.8kN$)
So, $W=mg=m\times9.8m/s^{2}$
This means that mass = $27800N\div9.8=2836.7 kg$
Acceleration given= $1.22m/s^{2}$
So, total Tension in cable is:
$W+ma= 27800N+(2836.7\times1.22)$
$W+ma=31.3kN$
