Answer
$F_{rope}=68 N$
Work Step by Step
Since the skier is moving at a constant velocity, there is no net force acting on them. After drawing a free body diagram, it can be concluded that the tension in teh rope must be equal to the horizontal component of weight parallel to the slope. This means that $$F_{rope}=mgsin\theta$$ Substituting known values of $m=50kg$, $g=9.8m/s^2$ and $\theta=8.0^{\circ}$ yields a force of $$F_{rope}=(50kg)(9.8m/s^2)sin(8.0^{\circ})$$ $$F_{rope}=68N$$
