Answer
The $net$ force accelerating each link $ =0.250$ $N$
Work Step by Step
We have,
$F_{net} = ma$
So, the $net$ force on each link is the product of mass of each link and the acceleration. Since all links are similar, the net force on each is the same.
Substituting the known values and solving gives:
$F_{net}= 0.100 \times 2.50 $
$F_{net}= 0.250 $ $N$
