Answer
Now, the acceleration is
$$\vec{a} =\left(13.0 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{i}}-\left(14.0 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{j}} $$
$\text { Using } \vec{F}_{\mathrm{nct}}=m \vec{a}(\text { with } m=0.025 \mathrm{\ kg}) \text { we now obtain } $
$$\vec{F}_{3}=(2.02 \mathrm{N}) \hat{\mathrm{i}}+(2.71 \mathrm{N}) \hat{\mathrm{j}} $$
Work Step by Step
Now, the acceleration is
$$\vec{a} =\left(13.0 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{i}}-\left(14.0 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{j}} $$
$\text { Using } \vec{F}_{\mathrm{nct}}=m \vec{a}(\text { with } m=0.025 \mathrm{\ kg}) \text { we now obtain } $
$$\vec{F}_{3}=(2.02 \mathrm{N}) \hat{\mathrm{i}}+(2.71 \mathrm{N}) \hat{\mathrm{j}} $$
