Answer
The extra distance between us and the object after one year is $~~1.0\times 10^{10}~m$
Work Step by Step
We can find the extra distance between us and the object after one year:
$v = H~R$
$\frac{d}{t} = H~r$
$d = H~r~t$
$d = (0.0218~m/s~ly)(1.5\times 10^4~ly)(365)(24)(3600~s)$
$d = 1.0\times 10^{10}~m$
The extra distance between us and the object after one year is $~~1.0\times 10^{10}~m$
