Answer
The corresponding hadron is $\Sigma^-$
Work Step by Step
The down quark $d$ has strangeness $0$, charge $-\frac{1}{3}$, and baryon number $+\frac{1}{3}$
The strange quark $s$ has strangeness $-1$, charge $-\frac{1}{3}$, and baryon number $+\frac{1}{3}$
The quark bundle $dds$ has net strangeness $-1$, net charge $-1$, and net baryon number $+1$
The corresponding hadron is $\Sigma^-$
