Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 44 - Quarks, Leptons, and the Big Bang - Problems - Page 1364: 26b

Answer

For combination $uus$, we have $$Q=+\frac{2}{3}+\frac{2}{3}-\frac{1}{3}=1 $$ and $$S=0+0-1=-1 . $$ Therefore this is $\Sigma^{+}$ particle.

Work Step by Step

For combination $uus$, we have $$Q=+\frac{2}{3}+\frac{2}{3}-\frac{1}{3}=1 $$ and $$S=0+0-1=-1 . $$ Therefore this is $\Sigma^{+}$ particle.
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