Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 44 - Quarks, Leptons, and the Big Bang - Problems - Page 1364: 31

Answer

The distance to the galaxy is $~~2.80\times 10^8~ly$

Work Step by Step

We can find the radial velocity of the galaxy relative to us: $v = \frac{\lambda-\lambda_0}{\lambda_0}~c$ $v = \frac{602.0~nm-590.0~nm}{590.0~nm}~c$ $v = 0.0203~c$ We can find the distance to the galaxy: $Hr = v$ $r = \frac{v}{H}$ $r = \frac{(0.0203)~(3.0\times 10^8~m/s)}{0.0218~m/s~ly}$ $r = 2.80\times 10^8~ly$ The distance to the galaxy is $~~2.80\times 10^8~ly$
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