Answer
$$=605 \mathrm{MeV}
$$
Work Step by Step
$\text {By using Eq. } 37-50 \text { , we get:} $
$$
\begin{aligned} Q &=-\Delta m c^{2}=\left(m_{\Sigma^{+}}+m_{K^{+}}-m_{\pi^{+}}-m_{p}\right) c^{2} \\ &=1189.4 \mathrm{MeV}+493.7 \mathrm{MeV}-139.6 \mathrm{MeV}-938.3 \mathrm{MeV} \\ &=605 \mathrm{MeV} \end{aligned}
$$
