Answer
The velocity when the ball reaches the target is $~~6.78~m/s$
Work Step by Step
In part (a), we found that the direction of the initial velocity is $\theta = 55.6^{\circ}$ above the horizontal.
Note that the velocity is horizontal when the ball reaches the target.
We can find the velocity when the ball reaches the target:
$v_x = (12.0~m/s)~cos~55.6^{\circ}$
$v_x = 6.78~m/s$
The velocity when the ball reaches the target is $~~6.78~m/s$
