Answer
$15.2\ s$
Work Step by Step
Given:
velocity of sprinter $v=9.2\ m/s$
radius of track $r=22.3\ m$
Time period of circular motion is $T=\frac{2\pi r}{v}$. Therefore;
$T=\frac{2\pi\times 22.3\ m}{9.2\ m/s} $
$T=15.2\ s$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 92: 120b
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