Answer
$r = 4.6\times 10^{12}~m$
Work Step by Step
We can find the minimum turning radius:
$a = \frac{v^2}{r}$
$r = \frac{v^2}{a}$
$r = \frac{(0.1~c)^2}{20~g}$
$r = \frac{[(0.1)~(3.0\times 10^8~m/s)]^2}{(20)(9.8~m/s^2)}$
$r = 4.6\times 10^{12}~m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 92: 121a
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